n^2-37n+342=0

Solution for n^2-37n+342=0 equation:

n^2-37n+342=0

a = 1; b = -37; c = +342;
Δ = b2-4ac
Δ = -372-4·1·342
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-1}{2*1}=\frac{36}{2}
=18
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+1}{2*1}=\frac{38}{2}
=19
$